Randomized query complexity can beat certificate complexity

📅 2026-09-14
📈 Citations: 0
Influential: 0
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🤖 AI Summary
本文通过构造一个函数,证明了随机查询复杂度可以显著小于证书复杂度,并且该函数的量子查询复杂度也得到了优化。
📝 Abstract
A long-standing open question in query complexity asks whether there is a total Boolean function f with R(f) << C(f), where R(f) and C(f) denote its bounded-error randomized query complexity and certificate complexity, respectively. We construct a function with R(f) = O~(sqrt{C(f)}), which is optimal up to log factors. The same function also has $Q(f) = O~(C(f)^{1/4}), where Q(f) is the bounded-error quantum query complexity of f, which is also nearly optimal.
Problem

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Randomized Query Complexity
Certificate Complexity
Boolean Function
Innovation

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randomized query complexity
certificate complexity
quantum query complexity